The signal $$\cos \left( {10\pi t + \frac{\pi }{4}} \right)$$   is ideally sampled at a sampling frequency of 15 Hz. The sampled signal is passed through a filter with impulse response $$\left( {\frac{{\sin \left( {\pi t} \right)}}{{\pi \tau }}} \right)\cos \left( {40\pi t - \frac{\pi }{2}} \right).$$     The filter output is

The signal $$\cos \left( {10\pi t + \frac{\pi }{4}} \right)$$   is ideally sampled at a sampling frequency of 15 Hz. The sampled signal is passed through a filter with impulse response $$\left( {\frac{{\sin \left( {\pi t} \right)}}{{\pi \tau }}} \right)\cos \left( {40\pi t - \frac{\pi }{2}} \right).$$     The filter output is Correct Answer $$\frac{{15}}{2}\cos \left( {40\pi t - \frac{\pi }{4}} \right)$$

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The input x(t) and output y(t) of a system are related as $$y\left( t \right) = \int\limits_{ - \infty }^t {x\left( \tau \right)} \cos \left( {3\tau } \right)d\tau .$$     The system is
Assertion (A): Nyquist rate of sampling is the theoretical minimum sampling rate at which the signal can be sampled and still be reconstructed from its samples. Reason (R): When the Nyquist rate sampling is used, only an ideal low pass filter can be used to extract signal x(t) from sampled signal xs(t). Code: