A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the and its top reaches a window 6 m about ground. Find the length of the ladder.

A 6.5 m
B 8.5
C 4.5
D 2.5 m

Correct Answer: 6.5 m

Let, AB be the ladder and AC be the Wall From Pythagoras theorem, we get, AB2 = BC2 + AC2 = (2.5)2 + (6)2 = 6.25 + 36 = 42.25⇒AB = 42.25.'.AB = 6.5The length of the ladder  = 6.5m
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