Solve : $$1\frac{1}{2}$$ + $$2\frac{2}{7}$$ = $$3\frac{1}{2}$$ + ?

Solve : $$1\frac{1}{2}$$ + $$2\frac{2}{7}$$ = $$3\frac{1}{2}$$ + ? Correct Answer $$\frac{2}{7}$$

Let the missing number be x
Given, $$1\frac{1}{2}$$ + $$2\frac{2}{7}$$ = $$3\frac{1}{2}$$ + x
x = $$1\frac{1}{2}$$ + $$2\frac{2}{7}$$ - $$3\frac{1}{2}$$
x = $$\frac{3}{2}$$ + $$\frac{16}{7}$$ - $$\frac{7}{2}$$
x = $$\frac{21 + 32 - 49}{14}$$
x = $$\frac{4}{14}$$
x = $$\frac{2}{7}$$
Hence, the number is $$\frac{2}{7}$$

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