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Which of the following is true about the finally clause in exception handling?

Which of the following is true about the finally clause in exception handling? Correct Answer The code in the finally block always executes, regardless of whether an exception is raised or not

Related Questions

Which of the following statements are TRUE about an SQL query? P: An SQL query can contain a HAVING clause even if it does not have a GROUP BY clause Q: An SQL query can contain a HAVING clause only if it has a GROUP BY clause R: All attributes used in the GROUP BY clause must appear in the SELECT clause S: Not all attributes used in the GROUP BY clause need to appear in the SELECT clause
You responsible for maintaining an application that was written by a former colleague at XYZ. The application reads from and writes to log files located on the local network. The original author included the following debugging code to facilitate maintenance: try {
Debug.WriteLine(“Inside Try”);
throw(new IOException());}
catch (IOException e) {
Debug.WriteLine (“IOException Caught”);}
catch (Exception e) {
Debug.WriteLine(“Exception Caught”);}.
finally {
Debug.WriteLine (“Inside Finally”);}
Debug.WriteLine (“After End Try”); Which output is produced by thus code?
What is the result of the following code snippet?

try {
int result = 10 / 0;
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} finally {
System.out.println("Finally Block!");
}
Select the statements which describe the correct usage of exception handling over conventional error handling approaches?
In C++, which of the following methods contained in the exception handling mechanism in a program fails to find a matching catch block for a raised exception?
What is the purpose of the "finally" block in Java exception handling?
What is the primary purpose of the `finally` block in a Java exception handling structure?
What is the result of the following code snippet?

try {
int num = 10 / 0;
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (Exception e) {
System.out.println("Exception!");
}
What is the result of the following code snippet?

try {
throw new ArithmeticException();
} catch (Exception e) {
System.out.println("Exception!");
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
}
What is the result of the following code snippet?

try {
throw new RuntimeException();
} catch (RuntimeException e) {
System.out.println("Runtime Exception!");
} catch (Exception e) {
System.out.println("Exception!");
}