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What is the result of the following code snippet?

try {
throw new RuntimeException();
} catch (RuntimeException e) {
System.out.println("Runtime Exception!");
} catch (Exception e) {
System.out.println("Exception!");
}

What is the result of the following code snippet?

try {
throw new RuntimeException();
} catch (RuntimeException e) {
System.out.println("Runtime Exception!");
} catch (Exception e) {
System.out.println("Exception!");
}
 Correct Answer Runtime Exception!

Related Questions

What is the result of the following code snippet?

try {
throw new ArithmeticException();
} catch (Exception e) {
System.out.println("Exception!");
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
}
What is the result of the following code snippet?

try {
int num = 10 / 0;
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (Exception e) {
System.out.println("Exception!");
}
Given the following piece of code:
class SalaryCalculationException extends Exception{}class Person{ public void calculateSalary() throws SalaryCalculationException{ //... throw new SalaryCalculationException(); //... }}class Company{ public void paySalaries(){ new Person().calculateSalary(); }}

Which of the following statements is correct?
1. This code will compile without any problems.
2. This code will compile if in method paySalaries() we return a boolean in stead of void.
3. This code will compile if we add a try-catch block in paySalaries().
4. This code will compile if we add throws SalaryCalculationException in the signature of method paySalaries().
What will be the result if NullPointerException occurs at line 2?
try{ //some code goes here}catch(NullPointerException ne){ System.out.print("1 ");}catch(RuntimeException re){ System.out.print("2 ");}finally{ System.out.print("3");}
You responsible for maintaining an application that was written by a former colleague at XYZ. The application reads from and writes to log files located on the local network. The original author included the following debugging code to facilitate maintenance: try {
Debug.WriteLine(“Inside Try”);
throw(new IOException());}
catch (IOException e) {
Debug.WriteLine (“IOException Caught”);}
catch (Exception e) {
Debug.WriteLine(“Exception Caught”);}.
finally {
Debug.WriteLine (“Inside Finally”);}
Debug.WriteLine (“After End Try”); Which output is produced by thus code?
What is the result of the following code snippet?

try {
String str = null;
System.out.println(str.length());
} catch (NullPointerException e) {
System.out.println("NullPointerException!");
} catch (Exception e) {
System.out.println("Exception!");
}
What will be the result after the class Test execution? class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); } } class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); } } class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); } } public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } } }
public class Threads2 implements Runnable { public void run() { System.out.println("run."); throw new RuntimeException("Problem"); Which among the following is true? } public static void main(String[] args) { Thread t = new Thread(new Threads2()); t.start(); System.out.println("End of method."); } } 
try{ File f = new File("a.txt");}catch(Exception e){}catch(IOException io){}

Is this code create new file name a.txt ?
What will be the output of the following piece of code: class Person{ public void talk() {} } public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); } }