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Consider the following code. int count = 0; void *thfun () { int ctr=0; for (ctr=0; ctr<100; ctr++)      count++; } If thfun is executed by two threads concurrently in a uniprocessor system, what will be the MINIMUM value of count when both threads complete their execution? Assume that count++ is performed using three instructions: (i) read value of count from memory to a CPU register R, (ii) increment R, and (iii) store the value of R in memory. 
Each of a set of n processes executes the following code using two semaphores a and b initialized to 1 and 0, respectively. Assume that count is a shared variable initialized to 0 and not used in CODE SECTION P. CODE SECTION P wait (a); count=count+1 ; if (count==n) signal (b) ; signal (a) ; wait (b) ; signal (b) ; CODE SECTION Q What does the code achieve?
Consider the following code snippet : var c = counter(), d = counter(); c.count() d.count() c.reset() c.count() d.count() The state stored in d is :
Quantity I: Mc Donald farm has only Emus and Lions, the total count of legs was 14 less than 4 times the total count of heads. How many legs are counted in total? Quantity II: Mc Donald Farm has only Emus and Lions, the total count of legs was 15 less than 5 times the total count of the head. How many legs are counted in total?
What will be the output of the following C program? void count (int n) { static int d=1; printf("%d ", n); printf("%d ", d); d++; if(n>1)   count (n-1); printf("%d ", d);    } void main() { count(3);   }
What is the output of the following code snippet:
count = 0
while count     print("Hello")
    count += 1
On a non-pipelined sequential processor, a program segment, which is a part of the interrupt service routine, is given to transfer 500 bytes from an I/O device to memory.     Initialize the address register     Initialize the count to 500 LOOP: Load a byte from device     Store in memory at address given by address register     Increment the address register     Decrement the count     If count! = 0 go to LOOP Assume that each statement in this program is equivalent to a machine instruction which takes one clock cycle to execute if it is a non-load/store instruction. The load-store instructions take two clock cycles to execute. The designer of the system also has an alternate approach of using the DMA controller to implement the same transfer. The DMA controller requires 20 clock cycles for initialization and other overheads. Each DMA transfer cycle takes two clock cycles to transfer one byte of data from the device to the memory. What is the approximate speedup when the DMA controller based design is used in place of the interrupt driven program based input-output?
What is the significance of the statement "HAVING COUNT (emp_id)>2" in the following MySQL statement?
SELECT d.name, COUNT (emp_id) emp_noFROM department d INNER JOIN Employee eON d.dept_id=e.emp_idGROUP BY d.nameHAVING COUNT (emp_id)>2
Wages of the workers are normally, the proportionality derived from their efficiency. But the concept of efficiency of labour is itself vague such as amount of physical output, output per man hour or output per man shift. But output is not the function of man alone. There are other factors which affect the output. Which among the following is/are not the factor(s) that would affect the output directly?
1. Physical condition of work
2. Nature of machinery
3. Technical process
4. Quality of raw material
5. System of management
6. Role of fellow workers
7. Competitors in the market
Consider the function fun1 shown below:   int fun1 (int num) {   int count = 0;   while (num)   { count ++;   num ≫= 1;   }   return (count); } The value returned by fun1 (435) is