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In Access press LEFT ARROW or CTRL+LEFT ARROW

In Access press LEFT ARROW or CTRL+LEFT ARROW Correct Answer Move the selected control to the left (except controls that are part of a layout)

In Microsoft Access, pressing the LEFT ARROW key or CTRL+LEFT ARROW is used to Move the selected control to the left. This action is applicable to controls within a form or report, allowing you to adjust the position of the selected control to the left, aligning it with other controls.

Option A: Pressing the RIGHT ARROW key or CTRL+RIGHT ARROW is used to Move the selected control to the right, aligning it with other controls on the form or report.
Option B: The correct option. Pressing the LEFT ARROW key or CTRL+LEFT ARROW moves the selected control to the left within the form or report.
Option C: Pressing the UP ARROW key or CTRL+UP ARROW is used to Move the selected control up, adjusting its position vertically.
Option D: None of the provided options are completely accurate. The correct option for moving a selected control to the left is Option B: Move the selected control to the left (except controls that are part of a layout).

Therefore, the correct option is Option B: Move the selected control to the left (except controls that are part of a layout).

Related Questions

The question below consists of a question and two statements. You have to decide whether the data provided in the statements are sufficient to answer the question and based on this give answer. Six arrows of different colours – Red, Green, Pink, Blue, White and Black are placed around a circular table facing the centre. Question: Which colour’s arrow is placed to the immediate left of black coloured arrow? Statements: I. Green coloured arrow is placed opposite to the white coloured arrow which is to the immediate left of pink coloured arrow. II. Red coloured arrow is placed opposite to blue coloured arrow and is placed adjacent to white coloured arrow.
A- Press DOWN ARROW or CTRL+DOWN ARROW , B- Press SHIFT+LEFT ARROW: 1- Move the selected control down, 2- Reduce the width of the selected control.
If a + b + c + d = 4, then find the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?
If a + b + c + d = 4, then the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?
In Access press UP ARROW or CTRL+UP ARROW
In Access press DOWN ARROW or CTRL+ DOWN ARROW
In Access press RIGHT ARROW or CTRL+RIGHT ARROW
The value of the expression $$\frac{{{{\left( {a - b} \right)}^2}}}{{\left( {b - c} \right)\left( {c - a} \right)}} + $$   $$\frac{{{{\left( {b - c} \right)}^2}}}{{\left( {a - b} \right)\left( {c - a} \right)}} + $$    $$\frac{{{{\left( {c - a} \right)}^2}}}{{\left( {a - b} \right)\left( {b - c} \right)}}$$   = ?
The Hamiltonian of a particle is given by $$H = \frac{{{p^2}}}{{2m}} + V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right) + \phi \left( { + \left| {\overrightarrow {\bf{r}} } \right|} \right)\overrightarrow {\bf{L}} .\overrightarrow {\bf{S}} ,$$        where $$\overrightarrow {\bf{S}} $$ is the spin, $$V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$  and $$\phi \left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$  are potential functions and $$\overrightarrow {\bf{L}} \left( { = \overrightarrow {\bf{r}} \times \overrightarrow {\bf{p}} } \right)$$   is the angular momentum. The Hamiltonian does not commute with
$$\frac{{{{\left( {4.53 - 3.07} \right)}^2}}}{{\left( {3.07 - 2.15} \right)\left( {2.15 - 4.53} \right)}} + \, $$     $$\frac{{{{\left( {3.07 - 2.15} \right)}^2}}}{{\left( {2.15 - 4.53} \right)\left( {4.53 - 3.07} \right)}} + \,\, $$     $$\frac{{{{\left( {2.15 - 4.53} \right)}^2}}}{{\left( {4.53 - 3.07} \right)\left( {3.07 - 2.15} \right)}}$$     is simplified to :