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If the electrostatic potential were Igiven by $$\phi = {\phi _0}$$  (x2 + y2 + z2), where $${\phi _0}$$ is constant, then the charge density giving rise to the above potential would be

If the electrostatic potential were Igiven by $$\phi = {\phi _0}$$  (x2 + y2 + z2), where $${\phi _0}$$ is constant, then the charge density giving rise to the above potential would be Correct Answer $$ - 6\,{\phi _0}{\varepsilon _0}$$

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