The Fourier transform of the function f(x) is $$F\left( k \right) = \int {{e^{ikx}}f\left( x \right)dx.} $$ The Fourier transform of $$\frac{{df\left( x \right)}}{{dx}}$$ is
The Fourier transform of the function f(x) is $$F\left( k \right) = \int {{e^{ikx}}f\left( x \right)dx.} $$ The Fourier transform of $$\frac{{df\left( x \right)}}{{dx}}$$ is Correct Answer -ikF(k)
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Feb 20, 2025
