The following equation needs to be numerically solved using the Newton-Raphson method. x3 + 4x - 9 = 0. The iterative equation for this purpose is (k indicates the iteration level)

$${{ ext{x}}_{{ ext{k}} + 1}} = rac{{2{ ext{x}}_{ ext{k}}^3 + 9}}{{3{ ext{x}}_{ ext{k}}^2 + 4}}$$

$${{ ext{x}}_{{ ext{k}} + 1}} = rac{{3{ ext{x}}_{ ext{k}}^2 + 4}}{{2{ ext{x}}_{ ext{k}}^2 + 9}}$$

$${{ ext{x}}_{{ ext{k}} + 1}} = {{ ext{x}}_{ ext{k}}} - 3{ ext{x}}_{ ext{k}}^2 + 4$$

$${{ ext{x}}_{{ ext{k}} + 1}} = rac{{4{ ext{x}}_{ ext{k}}^2 + 3}}{{9{ ext{x}}_{ ext{k}}^2 + 2}}$$

The following equation needs to be numerically solved using the Newton-Raphson method. x³ + 4x - 9 = 0. The iterative equation for this purpose is (k indicates the iteration level)

$${{\text{x}}_{{\text{k}} + 1}} = \frac{{2{\text{x}}_{\text{k}}^3 + 9}}{{3{\text{x}}_{\text{k}}^2 + 4}}$$

$${{\text{x}}_{{\text{k}} + 1}} = \frac{{3{\text{x}}_{\text{k}}^2 + 4}}{{2{\text{x}}_{\text{k}}^2 + 9}}$$

$${{\text{x}}_{{\text{k}} + 1}} = {{\text{x}}_{\text{k}}} - 3{\text{x}}_{\text{k}}^2 + 4$$

$${{\text{x}}_{{\text{k}} + 1}} = \frac{{4{\text{x}}_{\text{k}}^2 + 3}}{{9{\text{x}}_{\text{k}}^2 + 2}}$$

The following equation needs to be numerically solved using the Newton-Raphson method. x³ + 4x - 9 = 0. The iterative equation for this purpose is (k indicates the iteration level) Correct Answer $${{\text{x}}_{{\text{k}} + 1}} = \frac{{2{\text{x}}_{\text{k}}^3 + 9}}{{3{\text{x}}_{\text{k}}^2 + 4}}$$

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Feb 20, 2025

Engineering Maths
Numerical Methods

The following equation needs to be numerically solved using the Newton-Raphson method. x3 + 4x - 9 = 0. The iterative equation for this purpose is (k indicates the iteration level)

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The following equation needs to be numerically solved using the Newton-Raphson method. x³ + 4x - 9 = 0. The iterative equation for this purpose is (k indicates the iteration level)