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If y is the solution of the differential equation
$$\eqalign{ & {{\text{y}}^3}\frac{{{\text{dy}}}}{{{\text{dx}}}} + {{\text{x}}^3} = 0, \cr & {\text{y}}\left( 0 \right) = 1 \cr} $$
the value of y(-1) is

If y is the solution of the differential equation
$$\eqalign{ & {{\text{y}}^3}\frac{{{\text{dy}}}}{{{\text{dx}}}} + {{\text{x}}^3} = 0, \cr & {\text{y}}\left( 0 \right) = 1 \cr} $$
the value of y(-1) is Correct Answer 0

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