Related Questions

Parallelogram Law of Forces states, "if two forces acting simultaneously on a particle be represented in magnitude and direction by two adjacent sides of a parallelogram, their resultant may be represented in magnitude and direction by
A Its longer side
B Its shorter side
C The diagonal of the parallelogram which does not pass through the point of intersection of the forces
D The diagonal of the parallelogram which passes through the point of intersection of the forces
If two forces each equal to ‘T’ in magnitude act at right angles, their effect may be neutralized by a third force acting along their bisector in opposite direction whose magnitude will be
A 2T
B $$\frac{1}{2}{\text{T}}$$
C $$\sqrt 2 {\text{ T}}$$
D 3T
The change in length due to a tensile or compressive force acting on a body is given by (where P = Tensile or compressive force acting on the body, $$l$$ = Original length of the body, A = Cross-sectional area of the body and E = Young's modulus for the material of the body)
A $$\frac{{{\text{P}}l{\text{A}}}}{{\text{E}}}$$
B $$\frac{{{\text{P}}l}}{{{\text{AE}}}}$$
C $$\frac{{\text{E}}}{{{\text{P}}l{\text{A}}}}$$
D $$\frac{{{\text{AE}}}}{{{\text{P}}l}}$$
If two forces acting at a point are in equilibrium, they must be equal in magnitude and their line of action must be along
A The same line in the same sense
B The same line in opposite sense
C The perpendicular to both the lines
D None of these
A single force and a couple acting in the same plane upon a rigid body
A Balance each other
B Cannot balance each other
C Produce moment of a couple
D Are equivalent
The[ triangular base of a prism is a right triangle of sides a and b = 2a . The height h of the prism is equal to 10 mm and its volume is equal to 40 mm3 , what will be the lengths of the sides a and b of the triangle ?
A 2 mm and 3 mm
B 1 mm and 4 mm
C 2 mm and 2 mm
D 2 mm and 4 mm
A rigid body, under the action of external forces, can be replaced by two masses placed at a fixed distance apart. The two masses form an equivalent dynamical system, if
A The sum of the two masses is equal to the total mass of body
B The center of gravity of the two masses coincides with that of the body
C The sum of mass moment of inertia of the masses about their center of gravity is equal to the mass moment of inertia of the body
D All of the above
When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to
A $$\frac{1}{2}\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
B $$\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
C $$\frac{1}{2}\left( {{\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} } \right)$$
D $${\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
A triangle has a base x and an altitude y. A second triangle has a base twice the altitude of the first triangle, and an altitude twice the base of the first triangle. What is the area of the second triangle?
A 2xy
B 0.5xy
C 0.66xy
D 4xy
If three forces acting in one plane upon a rigid body, keep it in equilibrium, then they must either
A Meet in a point
B Be all parallel
C At least two of them must meet
D All the above are correct

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