A rigid body, under the action of external forces, can be replaced by two masses placed at a fixed distance apart. The two masses form an equivalent dynamical system, if

A The sum of the two masses is equal to the total mass of body
B The center of gravity of the two masses coincides with that of the body
C The sum of mass moment of inertia of the masses about their center of gravity is equal to the mass moment of inertia of the body
D All of the above

Correct Answer: All of the above

Bissoy MCQ
#Mechanical Engineering #Theory of Machine

Related Questions

Three forces acting on a rigid body are represented in magnitude, direction and line of action by the three sides of a triangle taken in order. The forces are equivalent to a couple whose moment is equal to
A Area of the triangle
B Twice the area of the triangle
C Half the area of the triangle
D None of these
If a rigid body is in equilibrium under the action of three forces, then
A These forces are equal
B The lines of action of these forces meet in a point
C The lines of action of these forces are parallel
D Both (B) and (C)
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A Concurrent
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A simple pendulum
B torsional pendulum
C compound pendulum
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A Simple pendulum
B Compound pendulum
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A One force only
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C One force and one couple only
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স্থির অবস্থায় থাকা একটি বস্তু বিস্ফরিত হয়ে m1 ও m2 ভরের দুইটি বস্তুতে পরিণত হয়ে যথাক্রমে v1 ও v2 বেগে বিপরীত দিকে চলমান। v1v2 এর অনুপাত কত? (A body initially at rest, exploded into two objects of masses m1 and m2 which are moving apart in opposite direction with speeds v1 and v2 respectively. What is the ratio v1v2?)
A m1m2
B m2m1
C -m2m1
স্থির অবস্থায় থাকা একটি বস্তু বিস্ফোরিত হয়ে m1 ও m2 ভরের দুইটি বস্তুতে পরিণত হয়ে যথাক্রমে v1 ও v2 বেগে বিপরীত দিকে চলমান। v1v2 এর অনুপাত কত? ( A body initially at rest, exploded into two objects of masses m and m which are moving apart in opposite direction with speeds v and v respectively. What is the ratio v1v2
A m1m2
B m2m1
C −m2m1
D m2m1

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