The polar moment of inertia of a solid circular shaft of diameter (D) is
A
$$\frac{{\pi {{\text{D}}^3}}}{{16}}$$
B
$$\frac{{\pi {{\text{D}}^3}}}{{32}}$$
C
$$\frac{{\pi {{\text{D}}^4}}}{{32}}$$
D
$$\frac{{\pi {{\text{D}}^4}}}{{64}}$$
Correct Answer: $$\frac{{\pi {{\text{D}}^4}}}{{32}}$$