Connie has a number of gold bars, all of different weights. She gives the 24 lightest bars, which weigh 45% of the total weight, to Brennan. She gives the 13 heaviest bars, which weigh 26% of the total weight, to Maya. She gives the rest of the bars to Blair. How many bars did Blair receive?

Connie has a number of gold bars, all of different weights. She gives the 24 lightest bars, which weigh 45% of the total weight, to Brennan. She gives the 13 heaviest bars, which weigh 26% of the total weight, to Maya. She gives the rest of the bars to Blair. How many bars did Blair receive? Correct Answer 15

The average weight of the bars given to Brennan (light) Let the total weight of all the bars be X.The weight of the bars given to Brennan, = 45% of X = 0.45XThe weight of the bars given to Maya, = 26% of X = 0.26XThe weight of the bars given to Claire = rest = 29% of X = 0.29XThe average weight of the bars given to Brennan,$$ = \frac{{{\text{Weight}}}}{{{\text{Number}}\,{\text{of}}\,{\text{bars}}}} = \frac{{0.45{\text{X}}}}{{24}}$$The average weight of the bars given to Maya = Weight / number of bars = $$\frac{{0.26{\text{X}}}}{{13}}$$Similarly, if the number of bars given to Blair = B, then the average weight of the bars given to Blair = $$\frac{{0.29{\text{X}}}}{{\text{B}}}$$As, the average weight of the bars given to Brennan (light) So , Option (B) is the right answer

Related Questions

Each of the statement consist of two statements I and II. You have to decide whether the data provided in the statement are sufficient to answer the question. Read both the statement and give the appropriate answer. Among five friends S, T, U, V and W who is 3rd heaviest? Statement I: S is the heaviest among all the five friends. Second lightest one having a weight of 58 kg. Statement II: T is the lightest among all the five friends. W is heavier than 58 kg, but lighter than V.