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An alloy contains the copper and aluminum in the ratio of 7 : 4 While making the weapons from this alloy, 12% of the alloy got destroyed. If there is 12 kg of aluminum in the weapon, then weight of the alloy required is :

An alloy contains the copper and aluminum in the ratio of 7 : 4 While making the weapons from this alloy, 12% of the alloy got destroyed. If there is 12 kg of aluminum in the weapon, then weight of the alloy required is : Correct Answer 37.5 kg

Copper : Aluminum = 7 : 4Let Copper and Aluminum in the weapon be 7x and 4x respectivelyGiven,Aluminum in weapon = 12 kgSo,→ 4x = 12→ x = 3Copper = 7x = 7 × 3 = 21 Kg.Total alloy in the weapon = 12 + 21 = 33 kgBut 12% alloy get destroyed in making the weapon, i.e. 88% alloy is used in the weapon, so, → 88 % alloy = 33 kg→ 100 % alloy = 37.5 kg

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