There are five boxes in a cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20% more than the weight of third box, whose weight is 25% more than the first box’s weight. The fourth box at 350 kg is 30% lighter than the fifth box. The difference in the average weight of the four heaviest boxes and the four lightest boxes is-

There are five boxes in a cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20% more than the weight of third box, whose weight is 25% more than the first box’s weight. The fourth box at 350 kg is 30% lighter than the fifth box. The difference in the average weight of the four heaviest boxes and the four lightest boxes is- Correct Answer 75 kg

Weight of first box = 200 kg
Weight of third box
= 125 % of 200 kg
= 250 kg
Weight of second box
= 120% of 250 kg
= 300 kg
Weight of fourth box = 350 kg
Let the weight of fifth box be x kg
Then, 70% of x = 350 kg
$$\eqalign{ & \Rightarrow x = \left( {\frac{{350 \times 100}}{{70}}} \right) \cr & \Rightarrow x = 500{\text{ kg}} \cr} $$.
Average weight of four heaviest boxes
$$\eqalign{ & {\text{ = }}\left( {\frac{{500 + 350 + 300 + 250}}{4}} \right){\text{kg}} \cr & {\text{ = 350 kg}} \cr} $$
Average weight of four lightest boxes
$$\eqalign{ & = \left( {\frac{{200 + 250 + 300 + 350}}{4}} \right){\text{kg}} \cr & = 275{\text{ kg}} \cr} $$
∴ Required difference
= (350 - 275)
= 75 kg

Related Questions

Each of the statement consist of two statements I and II. You have to decide whether the data provided in the statement are sufficient to answer the question. Read both the statement and give the appropriate answer. Among five friends S, T, U, V and W who is 3rd heaviest? Statement I: S is the heaviest among all the five friends. Second lightest one having a weight of 58 kg. Statement II: T is the lightest among all the five friends. W is heavier than 58 kg, but lighter than V.