A body is said to move with Simple Harmonic Motion if its acceleration, is

A Always directed away from the centre, the point of reference
B Proportional to the square of the distance from the point of reference
C Proportional to the distance from the point of reference and directed towards it
D Inversely proportion to the distance from the point of reference

Correct Answer: Proportional to the distance from the point of reference and directed towards it

Bissoy MCQ
#Civil Engineering #Applied Mechanics And Graphic Statics

Related Questions

The maximum acceleration of a particle moving with simple harmonic motion is
A ω
B ω.r
C ω2.r
D ω2/r
In simple harmonic motion, acceleration of a particle is proportional to
A Rate of change of velocity
B Displacement
C Velocity
D Direction
The acceleration of the particle moving with simple harmonic motion is _________ at the mean position.
A Zero
B Minimum
C Maximum
D None of these
The acceleration of a particle moving with simple harmonic motion, at any instant is given by
A $$\omega {\text{y}}$$
B $${\omega ^2}{\text{y}}$$
C $$\frac{{{\omega ^2}}}{{\text{y}}}$$
D $${\omega ^3}{\text{y}}$$
The acceleration of a particle moving with simple harmonic motion is __________ at the mean position.
A Zero
B Minimum
C Maximum
D None of these
সরল ছন্দিত স্পন্দকের ক্ষেত্রে বেগ ও ত্বরণ নির্ভর করে কোনটির উপর? (In simple harmonic motion the velocity and acceleration depends on-)
A ভর (mass)
B সরণ (displacement)
C আদিদশা (initial phase)
D ভরবেগ (momentum)
The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by (where, r = Amplitude of motion and y = Displacement of the particle from mean position.)
A $$\omega \sqrt {{{\text{y}}^2} - {{\text{r}}^2}} $$
B $$\omega \sqrt {{{\text{r}}^2} - {{\text{y}}^2}} $$
C $${\omega ^2}\sqrt {{{\text{y}}^2} - {{\text{r}}^2}} $$
D $${\omega ^2}\sqrt {{{\text{r}}^2} - {{\text{y}}^2}} $$
One end of a helical spring is fixed while the other end carries the load W which moves with simple harmonic motion. The frequency of motion is given by (where $$\delta $$ = Deflection of the spring.)
A $$2\pi \sqrt {\frac{g}{\delta }} $$
B $$\frac{1}{{2\pi }}\sqrt {\frac{g}{\delta }} $$
C $$2\pi \sqrt {\frac{\delta }{g}} $$
D $$\frac{1}{{2\pi }}\sqrt {\frac{\delta }{g}} $$
One end of a helical spring is fixed while the other end carries the load W which moves with simple harmonic motion. The frequency of motion is given by (where $$\delta $$ = Deflection of the spring)
A $$2\pi \sqrt {\frac{{\text{g}}}{\delta }} $$
B $$\frac{1}{{2\pi }}\sqrt {\frac{{\text{g}}}{\delta }} $$
C $$2\pi \sqrt {\frac{\delta }{{\text{g}}}} $$
D $$\frac{1}{{2\pi }}\sqrt {\frac{\delta }{{\text{g}}}} $$
When a body moves with simple harmonic motion, the product of its periodic time and frequency is equal to
A zero
B one
C п/2
D п

Next steps