The maximum bending moment due to a train of wheel loads on a simply supported girder

When a series of wheel loads crosses a simply supported girder, the maximum bending moment under any given wheel load occurs when

A

The centre of gravity of the load system is midway between the centre of span and wheel load under consi-deration

B

The centre of span is midway between the centre of gravity of the load system and the wheel load under consideration

C

The wheel load under consideration is midway between the centre of span and the centre of gravity of the load system

D

None of the above

The natural frequency of free transverse vibrations due to uniformly distributed load acting over a simply supported shaft is (where $$\delta {\text{S}}$$ = Static deflection of simply supported shaft due to uniformly distributed load)

A

$$\frac{{0.4985}}{{\sqrt {\delta {\text{S}}} }}$$

B

$$\frac{{0.5615}}{{\sqrt {\delta {\text{S}}} }}$$

C

$$\frac{{0.571}}{{\sqrt {\delta {\text{S}}} }}$$

D

$$\frac{{0.6253}}{{\sqrt {\delta {\text{S}}} }}$$

The natural frequency of free transverse vibrations due to a point load acting over a simply supported shaft is equal to (where $$\delta $$ = Static deflection of a simply supported shaft due to the point load)

A

$$\frac{{0.4985}}{{\sqrt \delta }}$$

B

$$\frac{{0.5615}}{{\sqrt \delta }}$$

C

$$\frac{{0.571}}{{\sqrt \delta }}$$

D

$$\frac{{0.6253}}{{\sqrt \delta }}$$

A shaft of diameter D is subjected to a twisting moment (T) and a bending moment (M). If the maximum bending stress is equal to maximum shear stress developed, then M is equal to

A

$$\frac{{\text{T}}}{2}$$

B

T

C

2T

D

4T

A simply supported beam carries varying load from zero at one end and w at the other end. If the length of the beam is a, the maximum bending moment will be

A

$$\frac{{{\text{wa}}}}{{27}}$$

B

$$\frac{{{\text{w}}{{\text{a}}^2}}}{{27}}$$

C

$$\frac{{{{\text{w}}^2}{\text{a}}}}{{\sqrt {27} }}$$

D

$$\frac{{{\text{w}}{{\text{a}}^2}}}{{9\sqrt 3 }}$$

If the sides of a slab simply supported on edges and spanning in two directions are equal, the maximum bending moment is multiplied by

A

0.2

B

0.3

C

0.4

D

0.5

The maximum bending moment of a simply supported beam of span $$l$$ and carrying a point load W at the center of beam, is

A

$$\frac{{{\text{W}}l}}{4}$$

B

$$\frac{{{\text{W}}l}}{2}$$

C

$${\text{W}}l$$

D

$$\frac{{{\text{W}}{l^2}}}{4}$$

If the maximum bending moment of a simply supported slab is M Kg.cm, the effective depth of the slab is (where Q is M.R. factor)

A

$$\frac{{\text{M}}}{{100{\text{Q}}}}$$

B

$$\frac{{\text{M}}}{{10\sqrt {\text{Q}} }}$$

C

$$\sqrt {\frac{{\text{M}}}{{\text{Q}}}} $$

D

$$\sqrt {\frac{{\text{M}}}{{100{\text{Q}}}}} $$

When a uniformly distributed load, shorter than the span of the girder, moves from left to right, then the conditions for maximum bending moment at a section is that

A

The head of the load reaches the section

B

The tail of the load reaches the section

C

The load position should be such that the section divides it equally on both sides

D

The load position should be such that the section divides the load in the same ratio as it divides the span

When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies

A

Less than the left half span

B

Whole of left half span

C

More than the left half span

D

Whole span

The maximum bending moment due to a train of wheel loads on a simply supported girder

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