Of three positive numbers, the ratio of the first and second numbers is 3:4 & that of the second and third numbers is 5:6. The product of the second and third numbers is 4320. What is the sum of three numbers?

Of three positive numbers, the ratio of the first and second numbers is 3:4 & that of the second and third numbers is 5:6. The product of the second and third numbers is 4320. What is the sum of three numbers? Correct Answer 177

Let the second & third numbers are 2x & 3x respectively. ATQ, 5x*6x = 4320 30*x*x = 4320 x*x = 144 x=12 Hence, second number = 5x = 5*12 = 60 Third number = 6x = 6*12 = 72 Ratio of first & second number = ¾ Hence, first number = ( ¾)*60 = 45 Sum of these 3 numbers = 60+72+45 = 177

Related Questions

Consider the 5 × 5 matrix \[{\text{A}} = \left[ {\begin{array}{*{20}{c}} 1&2&3&4&5 \\ 5&1&2&3&4 \\ 4&5&1&2&3 \\ 3&4&5&1&2 \\ 2&3&4&5&1 \end{array}} \right