If log 64 = 1.8061, then the value of log 16 will be (approx)?
If log 64 = 1.8061, then the value of log 16 will be (approx)? Correct Answer 1.2040
Given that, log 64 = 1.8061
i.e log43=1.8061
--> 3 log 4 = 1.8061
--> log 4 = 0.6020
--> 2 log 4 = 1.2040
⇒log42=1.2040
Therefore, log 16 = 1.2040
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Feb 20, 2025