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Which values of m would satisfy the equation 2log2m = 1 + log2((5m / 2) – 3)?

Which values of m would satisfy the equation 2log2m = 1 + log2((5m / 2) – 3)? Correct Answer 3, 2

Given, 2log2m = 1 + log2((5m / 2) – 3) ➩ log2m2 = log22 + log2((5m / 2) – 3) ➩ m2 = 2 ((5m / 2) – 3) ➩ m2 = 5m – 6 ➩ m2 – 5m + 6 = 0 ➩ m2 – 3m – 2m + 6 = 0 ➩ m (m – 3) – 2 (m – 3) = 0 ➩ (m – 3) (m – 2) = 0 ➩ m = 3, 2

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