A couple has 3 children. Each was born at a gap of 3 years and 4 months. If the age of the eldest brother is twice as old as the youngest brother, find the age of the middle brother.

A couple has 3 children. Each was born at a gap of 3 years and 4 months. If the age of the eldest brother is twice as old as the youngest brother, find the age of the middle brother. Correct Answer 10 years

Let the age of the youngest brother be x. Age of the eldest brother = x + (3 years 4 months) * 2 = x + 6 years 8 months It is given that age of the eldest brother is twice the age of the youngest brother. 2x = x + 6 years 8 months 2x – x = 6 years 8 months Age of the middle brother = age of the youngest brother + 3 years 4 months 6 years 8 months + 3 years 4 months = 10 years
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