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A liquid containing 60% of an acid is mixed with another liquid containing 40% of the acid in a ratio x : y. If the percentage of acid in the final mixture is 47.5%, find the ratio x : y.

A liquid containing 60% of an acid is mixed with another liquid containing 40% of the acid in a ratio x : y. If the percentage of acid in the final mixture is 47.5%, find the ratio x : y. Correct Answer 3 : 5

The ratio in which the liquids are mixed = x : y. X : y = (47.5 – 40) : (60 – 47.5) = 7.5 : 12.5 = 3 : 5

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