A mixture containing 35% acid is mixed in another liquid containing x% acid in a ratio 3 : 2. If the percentage of acid in the final solution is 30%, find the value of x.

A mixture containing 35% acid is mixed in another liquid containing x% acid in a ratio 3 : 2. If the percentage of acid in the final solution is 30%, find the value of x. Correct Answer 22.5

The mixtures are mixed in a ratio 3 : 2. Let the quantity of the mixtures mixed be 300 liters and 200 liters, respectively. The quantity of acid in the first mixture = 35% of 300 = 105 liters The quantity of acid in the second mixture = x% of 200 = 2x The quantity of acid in the final mixture = 30% of 500 = 150 liters 2x + 105 liters = 150 liters, 2x = 45 liters, x = 45 / 2 = 22.5
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