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Put the statements in an order to divide the line AB into 10 parts using the principle of diagonal scales. i. Number the division-points as 1, 2, 3, up to 9 starting from C and later join AC. ii. Divide the line BC into 10 equal parts. iii. Draw a perpendicular line BC TO the line AB. iv. Hence 9’9 is 0.9AB and similarly, other 2’2 is 0.2AB. v. Number the cutting points on AC as 1’, 2’, 3’ and so on up to 9’. vi. Draw lines parallel to AB through the division-points.

Put the statements in an order to divide the line AB into 10 parts using the principle of diagonal scales. i. Number the division-points as 1, 2, 3, up to 9 starting from C and later join AC. ii. Divide the line BC into 10 equal parts. iii. Draw a perpendicular line BC TO the line AB. iv. Hence 9’9 is 0.9AB and similarly, other 2’2 is 0.2AB. v. Number the cutting points on AC as 1’, 2’, 3’ and so on up to 9’. vi. Draw lines parallel to AB through the division-points. Correct Answer iii, ii, i, vi, v, iv

In the principle of the diagonal scale we apply the concept of similar triangles. So, we need to draw a perpendicular to B, say BC and form a right angle triangle ABC. By dividing the line BC into 10 equal parts (required number of parts as mentioned in the question) and drawing lines parallel to AB through division points, all these lines give the measurement as 0.1AB, 0.2 AB, 0.3AB, 0.4AB and so on up to 0.9AB.

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