The sum of internal angles of a regular polygon of n sides is equal to _________

The sum of internal angles of a regular polygon of n sides is equal to _________ Correct Answer (2n-4) x 900

A regular polygon of n sides subtends a total angle of 3600 at the center, with n isosceles triangles meeting at it. The identical sides of each isosceles triangular are equal to the radii of the circle circumscribing the polygon and they subtend semi-internal angles at each end of the sides of the polygon.

Related Questions

Given that the angles of a polygon are all equal and each angle is a right angle. Statement 1: The quadrilateral has exactly four sides Statement 2: The sum of the angles of a polygon having n sides is (3n - 8) right angles. Which one of the following is correct in respect of the above statements?