Find the specific output of a tractor engine of stroke length 17 cm, bore 15 cm with brake power 30 Hp.

Find the specific output of a tractor engine of stroke length 17 cm, bore 15 cm with brake power 30 Hp. Correct Answer 12 Hp/l

Specific output = Brake power/A*L     where A – Area and L – stroke length = 30/((π*0.152)/4)*0.17 = 9986.19 Hp/m3 = 9.98619 Hp/l

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The brake power (B.P.) of the engine is given by (where W = Brake load or dead load in newtons, $$l$$ = Length of arm in meters, N = Speed of engine in r.p.m., S = Spring balance reading in newtons, D = Diameter of brake drum in meters and d = Diameter of rope in meters)