Find indicated power of a two-cylinder four-stroke engine with mean effective pressure of 686700 N/m2, stroke length 15 cm, bore 12.5 cm and rpm as 1200.

Find indicated power of a two-cylinder four-stroke engine with mean effective pressure of 686700 N/m2, stroke length 15 cm, bore 12.5 cm and rpm as 1200. Correct Answer 33 Hp

Indicated power = k.Pm.L.A.n/60 = (2*686700 N/m2*0.15m*(π*(0.125m)2/4)*1200/2)/60 = 25281.23 watts = 33.90 Hp

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The indicated power of a four stroke engine (in watts) is equal to (where P = Mean effective pressure in N/m2, L = Length of stroke in metres, A = Cross-sectional area of the piston in m2 and N = Speed of the engine in revolutions per second (r.p.s)