In a particular enzyme-catalyzed reaction, Vmax = 0.2 mol/sec and Km = 5 mM. Assume the enzyme shows standard Michaelis-Menten kinetics. What is the rate of the reaction when = 10 mM?

In a particular enzyme-catalyzed reaction, Vmax = 0.2 mol/sec and Km = 5 mM. Assume the enzyme shows standard Michaelis-Menten kinetics. What is the rate of the reaction when = 10 mM? Correct Answer = 10 mM? ] 0.133

v = Vmax / (Km + ) = 0.2×10 / (5+10) = 0.133.
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