The specific angular momentum of a hyperbolic trajectory is 94,000 km2/s and the altitude of satellite from earth’s surface is 30,850 km. What is the tangential velocity of the satellite trajectory?

The specific angular momentum of a hyperbolic trajectory is 94,000 km2/s and the altitude of satellite from earth’s surface is 30,850 km. What is the tangential velocity of the satellite trajectory? Correct Answer 2.525 km/s

Given, Satellite altitude from earth (z) = 30,850 km Specific angular momentum (h) = 94,000 km2/s Tangential velocity (vT) = h/r = 94,000/(30,850 + 6378) = 2.525 km/s
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