What is the specific angular momentum of an elliptical orbit, if the flight path angle of the satellite in orbit at an instant is 15°? The satellite is travelling at a velocity of 10.7 km/s at the same instant and is parked at an altitude of 7048 km measured from earth’s center.

What is the specific angular momentum of an elliptical orbit, if the flight path angle of the satellite in orbit at an instant is 15°? The satellite is travelling at a velocity of 10.7 km/s at the same instant and is parked at an altitude of 7048 km measured from earth’s center. Correct Answer 72,876.32 km2/s

Given, Velocity of satellite (v) = 10.7 km/s Flight path angle (γ) =15° Satellite distance (r) = 7048 km Tangential velocity (vt) = vcos(γ) = 10.7*cos(15°) = 10.34 km/s Specific angular momentum (h) = rvt = 7048*10.34 = 72,876.32 km2/s
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