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According to Von-mises yielding occur when J2 Exceeded some constant k2 So, the minimum condition for yielding is J2 = k2 Find the value of k in state of pure shear. Given that yield strength in pure torsion = τ.

According to Von-mises yielding occur when J2 Exceeded some constant k2 So, the minimum condition for yielding is J2 = k2 Find the value of k in state of pure shear. Given that yield strength in pure torsion = τ. Correct Answer τ

In the state of pure shearσ1= -σ3= τ andσ2=0 Condition for yielding 1/6 =k2 => 1/6 => 1/6(6 τ2) = τ2 So τ2=k2 => k = τ So, the constant k is equal to yield strength in pure torsion.

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