According to Von-mises, yielding occurs when J2 exceeds some constant k2 So, the minimum condition for yielding is J2=k2 Find the value of k in uniaxial tension. Given that yield strength = σo

According to Von-mises, yielding occurs when J2 exceeds some constant k2 So, the minimum condition for yielding is J2=k2 Find the value of k in uniaxial tension. Given that yield strength = σo Correct Answer σo/√3

In the case of uniaxial tension => σ1 = σo, σ2=0, σ3=0 So according to the condition J2 = k2 => J2 = 1/6 => J2 = 1/6 => J2 = 1/3 J2 = k2 => 1/3 = k2 => k = σo/√3.

Related Questions

The final result for von-Mises theory for the distortion relating the yield stress with stress deviator is: σo = 1/√2 1/2 Where σo yield stress in uniaxial tension.