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For the given chemical reaction C6H14 + 19/2 O2 → 6 CO2+ 7 H2O 7. If the required amount of CO2 is 440 kg/hour then how much kg of C6H14 should be burned per hour?

For the given chemical reaction C6H14 + 19/2 O2 → 6 CO2+ 7 H2O 7. If the required amount of CO2 is 440 kg/hour then how much kg of C6H14 should be burned per hour? Correct Answer 143.33

1 mole of C6H14 = 6 moles of CO2.

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