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A gas mixture with 50% Ar with pressure 80 Pa at 0oC at the rate 5 liter/s is passed through a reactor and products a gas mixture with 80% Ar with pressure 50 Pa at 27oC, what is the rate of product?

A gas mixture with 50% Ar with pressure 80 Pa at 0oC at the rate 5 liter/s is passed through a reactor and products a gas mixture with 80% Ar with pressure 50 Pa at 27oC, what is the rate of product? Correct Answer 5 liter/s

Ar balance: 0.5*80*5 = 0.8*50*P, => P = 5 liter/s.

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