Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is ----

A 36
B 45
C 48
D 49

Correct Answer: 48

আপেক্ষিক বেগ = (60 + 90) km/hr = 150×518 m/s = 1253 m/s দূরত্ব অতিক্রম করতে হবে (1.10 + 0.9)km = 2km = 2000m ∴ নির্ণেয় সময় = 2000m1253m/s = 48s
Bissoy MCQ
#গণিত #ট্রেন ও  গতিবেগ (Train & Speed) #United Commercial Bank Ltd (UCB) #United Commercial Bank Ltd - Probationary Officer - 17.02.2017

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