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The efficiency of Carnot heat engine is 40%. What is the value of C.O.P. of a refrigerator operating on reversed Carnot cycle?

The efficiency of Carnot heat engine is 40%. What is the value of C.O.P. of a refrigerator operating on reversed Carnot cycle? Correct Answer 1.5

ηE = 40% = 0.4 C.O.P. of heat pump = 1 / ηE = 1 / 0.4 = 2.5 As we know, (C.O.P.)R = (C.O.P.)P − 1 C.O.P. of refrigerator = 2.5 − 1 = 1.5.

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