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An epicyclic gear train has 3 shafts A,B and C. A is an input shaft running at 100 r.p.m. clockwise. B is an output shaft running at 250 r.p.m. clockwise. Torque on a is 50 kNm. C is a fixed shaft. The torque to fix C

An epicyclic gear train has 3 shafts A,B and C. A is an input shaft running at 100 r.p.m. clockwise. B is an output shaft running at 250 r.p.m. clockwise. Torque on a is 50 kNm. C is a fixed shaft. The torque to fix C Correct Answer is 20 kNm anticlockwise

TA ωA = TB ωB 50 x 100 = TB x 250 or, TB = 20 kNm Torque on C will be same as on B but in inverse direction.

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