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The radial distance from the top of a tooth to the bottom of a tooth in a meshing gear, is called

The radial distance from the top of a tooth to the bottom of a tooth in a meshing gear, is called Correct Answer clearance

Clearance is the radial distance from the top of the tooth to the bottom of the tooth, in a meshing gear. A circle passing through the top of the meshing gear is known as clearance circle.

Related Questions

A gear train consist of spur gear as shown. Gear A receives 4kW of power at 750rpm through its shaft and rotates in CW direction. A gear train consist of spur gear as shown. Gear A receives 4kW of power at 750rpm through its shaft and rotates in CW direction. Calculate the torque on the gear C if number of teeth on gear A, B and C are 40, 70 and 30.
A planetary gear train is shown in the figure. Number of teeth on the sun gear A, planet gear B and fixed ring gear D are given by 30, 70 and 140 respectively. Module is taken as 5mm. A pair of spur gears consist of 25 teeth pinion meshing with a 115 teeth gear. The module is 5mm. Calculate the gear ratio.
A gear train consist of spur gear as shown. Gear A receives 4kW of power at 750rpm through its shaft and rotates in CW direction. Calculate the tangential gear tooth force. Module of the gear is 5mm.
A planetary gear train is shown in the figure. Number of teeth on the sun gear A, planet gear B and fixed ring gear D are given by 30, 70 and 140 respectively. Module is taken as 5mm. Calculate the tangential component of gear tooth force.
Following is the data for transmission system of a Gear box reduction ratios.
1st gear - 4.3 : 1
2nd gear - 3.00 : 1
3rd gear - 2.71 : 1
4th gear - 1 : 1
Final drive reduction is 5.0 : 1
The overall reduction when the vehicle is driven in 2nd gear is
In a reverted gear train, two gears P and Q are meshing, Q-R is a compound gear, and R and S are meshing. The modules of P and R are 4 mm and 5 mm respectively. The numbers of teeth in P, Q and r are 20, 40 and 25 respectively. The number of teeth in S is
Calculate the radial component of gear tooth force if power transmitted is 6kW and diameters of pinion and gear are 150mm and 210 mm with face width of tooth being 35mm. Power is transmitted at 3000rpm. Also pressure angle is 20⁰.
Consider the following statements regarding gear tooth designing for gear drive: 1. Tooth profiles not designed as per ‘law of gearing’ will cause vibration and impact problems even at low speed. 2. As the gears go through their mesh, the pitch point must remain stationary on the line of centres. 3. In a correctly designed tooth profile, the line of action of successive instantaneous points of contact will pass through the stationary pitch point. Which of the above statements are correct?
The velocity of sliding of meshing gear teeth is
(Where $${\omega _1}$$ and $${\omega _2}$$ are angular velocities of meshing gears and ‘y’ is distance between point of contact and the pitch point)
The interference between a given pinion tooth and a gear tooth can be avoided by using 1. smaller pressure angle 2. larger pressure angle 3. Less number of teeth on the gear for a pinion with predefined number of teeth 4. More number of teeth on the gear for a pinion with predefined number of teeth Which of the above statements are correct?