A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle executes simple harmonic motion with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is?

A

T/12

B

T/8

C

T/4

D

T/2

Which one of the following is the correct sequence of various stages of operating cycle of a manufacturing company? 1. Raw material conversion period, work-in-progress conversion period, Finished goods conversion period, Receivables conversion period 2. Raw material conversion period, work-in-progress conversion period, Creditors payment period, Receivables conversion period 3. Creditor payment period. Raw material conversion period, Receivables conversion period, work-in- progress conversion period 4. Raw material conversion period, Finished goods conversion period, work-in- progress conversion period. Receivables conversion period

A

1

B

2

C

3

D

4

A particle executes simple harmonic oscillation. Its amplitude is a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is___________

A

T/8

B

T/12

C

T/2

D

T/4

A particle executes simple harmonic motion, its time period is 16s. If it passes through the centre of oscillation, then its velocity is 2 m/s at time 2s. The amplitude will be ___________

A

7.2m

B

4cm

C

6cm

D

0.72m

A particle is executing simple harmonic motion of amplitude 10cm. Its time period of oscillation is π seconds. The velocity of the particle when it is 2 cm from extreme position is ___________

A

10 cm/s

B

12 cm/s

C

16√16 cm/s

D

16 cm/s

A particle executes simple harmonic motion with an angular velocity of 3.5 rad/sec and maximum velocity acceleration 7.5 m/s2 respectively. What is the amplitude of oscillations?

A

0.28m

B

0.36m

C

0.707m

D

Zero

A particle executes simple harmonic motion of amplitude A. At what distance from the mean position is its kinetic energy equal to its potential energy?

A

0.51A

B

0.71A

C

0.61A

D

0.81A

Consider the following statements.
A Simple Pendulum is set into oscillation. Then,
1. the acceleration is zero when the bob passes through the mean position.
2. in each cycle the bob attains a given velocity twice.
3. both acceleration and velocity of the bob are zero when it reaches its extreme position during the oscillation.
4. the amplitude of oscillation of the simple pendulum decreases with time.
Which of these statements are correct?

A

Only 1 and 2

B

Only 3 and 4

C

Only 1, 2 and 4

D

Only 2, 3 and 4

The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by (where, r = Amplitude of motion and y = Displacement of the particle from mean position.)

A

$$\omega \sqrt {{{\text{y}}^2} - {{\text{r}}^2}} $$

B

$$\omega \sqrt {{{\text{r}}^2} - {{\text{y}}^2}} $$

C

$${\omega ^2}\sqrt {{{\text{y}}^2} - {{\text{r}}^2}} $$

D

$${\omega ^2}\sqrt {{{\text{r}}^2} - {{\text{y}}^2}} $$

Wave has simple harmonic motion whose period is 4seconds while another wave which also possesses simple harmonic motion has its period 3sec. If both are combined, then the resultant wave will have the period equal to ___________

A

4sec

B

5sec

C

12sec

D

3sec

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

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