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A particle executes simple harmonic motion with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is?

A particle executes simple harmonic motion with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is? Correct Answer T/12

y=asinωt a/2=asin⁡(2π/T)t sin⁡(2π/T)t=sin⁡(π/6) 2π/T×t=π/6 or t=T/12.

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