Bissoy.com
Doctors Medicines MCQs Q&A

What is the overall length of fillet weld to be provided for lap joint to transmit a factored load of 100kN? Assume site welds and width and thickness of plate as 75mm and 8mm respectively, Fe410 steel.

What is the overall length of fillet weld to be provided for lap joint to transmit a factored load of 100kN? Assume site welds and width and thickness of plate as 75mm and 8mm respectively, Fe410 steel. Correct Answer 201mm

Minimum size of weld = 3mm Maximum size of weld = 8-1.5 = 6.5mm Assume size of weld = 5mm Effective throat thickness = 0.7 x 5 = 3.5mm Strength of weld = 3.5×410/(√3 x1.5) = 552.33 N/mm Required length of weld = 100 x 103/552.33 = 181.05 mm length to be provided on each side = 181/2 = 90.5mm End return = 2×5 = 10mm Overall length = 2 x (90.5 + 2 x 5) = 201mm.

Related Questions

Two plates of 12mm and 16mm thickness are to be joined by groove weld. The joint is subjected to factored tensile load of 400kN. Due to some reasons the effective length of weld that could be provided was 150mm only. What is the safety of joint if single-V groove weld is provided?
With reference to the following figure, a plate, 75mm wide and 10mm thick, is joined with another plate as shown. The permissible tensile and shear stress in the welds are 50/mm² and 40N/mm². Determine the required length of each parallel fillet weld if length of transverse weld is 40mm.
A fillet-welded joint is subjected to transverse loading F as shown in the figure. Both legs of the fillets are of 10 mm size and the weld length is 30 mm. If the allowable shear stress of the weld is 94 MPa, considering the minimum throat area of the weld, the maximum allowable transverse load per weld in kN is
The permissible stress in the fillet weld is 100 N/mm². The fillet weld has equal leg lengths of 15 mm each. The allowable shearing load on the weldment per cm length of the weld is
Which of the following statements are correct in respect of welded connections? 1) Strength of Butt weld is equal to the strength of components joined. 2) Fillet welds carry the loads computed based on the tensile strength characteristics of fusion material. 3. for effective transmission of load by fillet weld, the fusion faces shall subtend an angle between 60° and 120° 
A steel column of ISHB 350 @72.4 kg/m is subjected to a factored axial compressive load of 2000 kN. The load is transferred to a concrete pedestal of grade M20 through square base plate. Consider the bearing strength of concrete as 0.45 fck, where fck is the characteristic strength of concrete. Using limit state method and neglecting the self-weight of base plate and steel column, the length of a side of the base plate to be provided is
The bracket welded to the vertical plate by means of two fillet welds. Calculate size of the welds if P=40kN, leg=4mm and e=400mm. Maximum permissible value of shear stress in the weld is 70N/mm².
A double fillet welded joint with parallel fillet weld of length '$$l$$' and leg 's' is subjected to a tensile force 'P'. Assuming uniform stress distribution, the shear stress in the weld is given by
A steel plate is subjected to tension. The tensile force is applied over a width 'a' whereas the gross width of the plate is 'b'. The dispersion of the force from the point of application is at about 30° with the axis and extends to a maximum width of 12 times the thickness t of the plate. The effective width which comes into action will be
The tensile strength of the welded joint for double fillet is (where s = Leg or size of the weld, $$l$$ = Length of weld and $${\sigma _{\text{t}}}$$ = Allowable tensile stress for weld metal)