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The centre line method is suitable for walls having ________

The centre line method is suitable for walls having ________ Correct Answer Similar cross-sections

The centre line method is suitable for walls having similar cross-sections. The estimates prepared using the centre line method are the quickest and accurate.

Related Questions

Dipu wants to paint all the four walls of his room. All the walls are of rectangular shape and opposite walls are of same measurement. If the size of the walls are 4 m x 3.5 m and 4.5 m × 3.5 m and cost to paint the wall is Rs. 22 per square meter, what will be the total cost to paint the walls?
Given are the steps to draw a perpendicular to a line at a point within the line when the point is near the centre of line. Arrange the steps. Let AB be the line and P be the point in it i. Join F and P which is perpendicular to AB. ii. Now C as centre take the same radius and cut the arc at D and again D as centre with same radius cut the arc further at E. iii. With centre as P take any radius and draw an arc (more than a semicircle) cuts AB at C. iv. Now D, E as centre take radius (more than half of DE) draw arcs which cut at F.
Seven people A, B, C, D, E, F and G live on separate floors of a 7-floor building. Ground floor is numbered 1, first floor is numbered. 2 and so on until the topmost floor is numbered 7. Each one of these having a different cars-Cadillac, Ambassador, Fiat, Maruti, Mercedes, Bedford and Fargo but not necessarily in the same order. Only three people live above the floor on which A lives. Only one person lives between A and the one having a car Cadillac. F lives immediately below the one having a car Bedford. The one having a car Bedford lives on an even-numbered floor. Only three people live between the ones having a car Cadillac and Maruti. E lives immediately above C. E is not having a car Maruti. Only two people live between B and the one having a car Fargo. The one having a car Fargo lives below the floor on which B lives. The one having a car Fiat does not live immediately above D or immediately below B. D does not live immediately above or immediately below A. G does not have a car Ambassador. Question : How many people live between the floors on which D and the one having a car Bedford ?
Given are the steps to draw a perpendicular to a line at a point within the line when the point is near the centre of a line. Arrange the steps. Let AB be the line and P be the point in it i. P as centre, take convenient radius R1 and draw arcs on the two sides of P on the line at C, D. ii. Join E and P iii. The line EP is perpendicular to AB iv. Then from C, D as centre, take R2 radius (greater than R1), draw arcs which cut at E.
Load-bearing walls are defined as those walls which carry their own weight only whereas non-load bearing walls are defined as those walls which can carry superimposed loads in addition to their own weight.
In the centre line method of working out volumes, for T junction of walls, what deductions must be made from the centre line length at each junction?
Given are the steps to draw a perpendicular to a line from a point outside the line, when the point is nearer the centre of line. Arrange the steps. Let AB be the line and P be the point outside the line i. Take P as centre and take some convenient radius draw arcs which cut AB at C, D. ii. Join E, F and extend it, which is perpendicular to AB. iii. From C, D with radius R1 (more than half of CD), draw arcs which cut each other at E. iv. Again from C, D with radius R2 (more than R1), draw arcs which cut each other at F.
Construction of cavity walls as external walls to protect the building from the outside heat or cold as the hollow space between two walls act as an ________
Given are the steps to draw a perpendicular to a line from a point outside the line, when the point is near the centre of line. Arrange the steps. Let AB be the line and P be the point outside the line i. The line EP is perpendicular to AB ii. From P take convenient radius and draw arcs which cut AB at two places, say C, D. iii. Join E and P. iv. Now from centers C, D draw arc with radius (more than half of CD), which cut each other at E.
Given are the steps to draw a perpendicular to a line from a point outside the line, when the point is near an end of the line. Arrange the steps. Let AB be the line and P be the point outside the line i. The line ED is perpendicular to AB ii. Now take C as centre and CP as radius cut the previous arc at two points say D, E. iii. Join E and D. iv. Take A as center and radius AP draw an arc (semicircle), which cuts AB or extended AB at C.