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In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the 5th harmonic from the output voltage waveform, the value of the pulse width (2d) must be equal to

In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the 5th harmonic from the output voltage waveform, the value of the pulse width (2d) must be equal to Correct Answer

To eliminate the nth harmonic, nd = π. Therefore, d = π/n = π/5 = 36° Hence, 2d = 72°.

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