In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the nth harmonic from the output voltage

In case of a single-pulse width modulation with the pulse width = 2d, to eliminate the nth harmonic from the output voltage Correct Answer nd = π

To eliminate, the nth harmonic, nd is made equal to π radians, or d = π/n. From the below expression, when nd = π. sin nd = 0 hence, that output voltage harmonic is eliminated.
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