The circuit shown below has the following parameters: Voltage drop across D1 & D2 = 0.7 Volts V1 = 8 Volts V2 = 6 Volts Vs = 10V/√2 (RMS) At the load (R), the peak value in the negative half cycle is

The circuit shown below has the following parameters: Voltage drop across D1 & D2 = 0.7 Volts V1 = 8 Volts V2 = 6 Volts Vs = 10V/√2 (RMS) At the load (R), the peak value in the negative half cycle is Correct Answer 6.7 V

In the negative half, only D2 is active. Hence use KVL, Vo = 6 + 0.7 Volts.

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