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The circuit shown below has the following parameters: V1 = 8 Volts V2 = 6 Volts Vs = 10V/√2 (rms) Voltage drop across D1 & D2 = 0.7 Volts At the load (R), the peak value in the positive half cycle will be

The circuit shown below has the following parameters: V1 = 8 Volts V2 = 6 Volts Vs = 10V/√2 (rms) Voltage drop across D1 & D2 = 0.7 Volts At the load (R), the peak value in the positive half cycle will be Correct Answer 8.7 V

In the positive half, only D1 is active. Hence use KVL, Vo = 8 + 0.7 Volts.

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