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A diode circuit is so arranged that when the switch is open it’s KVL gives Ri+ 1/C ∫i dt = 0 When the switch is closed, Ri+ 1/C ∫i dt = Vs Vs is the dc supply voltage. The diode is so connected that it is forward biased when switch is closed The circuit is mostly likely be a

A diode circuit is so arranged that when the switch is open it’s KVL gives Ri+ 1/C ∫i dt = 0 When the switch is closed, Ri+ 1/C ∫i dt = Vs Vs is the dc supply voltage. The diode is so connected that it is forward biased when switch is closed The circuit is mostly likely be a Correct Answer diode in series with the switch, R, C & Vs

Examine the equation, the same current flows through R & C. Also when switch is open, the equation R.H.S is 0. Hence, all the elements are in series.

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