Bissoy.com
Doctors Medicines MCQs Q&A

Why closed loop differential amplifiers are difficult to null?

Why closed loop differential amplifiers are difficult to null? Correct Answer Due to compensating network

The closed loop differential amplifiers are more difficult to null because the use of compensating network can change the common mode rejection mode.

Related Questions

Consider two relations R1(A, B) with the tuples (1, 5), (3, 7) and R2(A, C) = (1, 7), (4, 9). Assume that R(A, B, C) is the full natural outer join of R1 and R2. Consider the following tuples of the form (A, B, C): a = (1, 5, null), b = (1, null, 7), c = (3, null, 9), d = (4, 7, null), e = (1, 5, 7), f = (3, 7, null), g = (4, null, 9). Which one of the following statements is correct?
The mixing vat in a factory receives liquid ingredients through six separate value--- labeled R.S.T.U,Y and Z -- each of which has exactly two settings: open and closed.The mixing vat operator must ensure that each valve is set open or closed according to the following conditions: If T is open, both S and Z must be closed, R and Z cannot both be closed at the same time; If Y is closed, Z must also be closed;S and U cannot both be open at the same time. If the maximum number of valves that can be closed at the same time are closed which of the following must true?
The mixing vat in a factory receives liquid ingredients through six separate value--- labeled R.S.T.U,Y and Z -- each of which has exactly two settings: open and closed.The mixing vat operator must ensure that each valve is set open or closed according to the following conditions: If T is open, both S and Z must be closed, R and Z cannot both be closed at the same time; If Y is closed, Z must also be closed;S and U cannot both be open at the same time. If R is closed and U is open, which of the following must be true?
Consider the following statements in connection with deflection-type and null-type instruments: 1. Null-type instruments are more accurate than the deflection-type ones. 2. Null-type of instrument can be highly sensitive compared to a deflection-type instrument. 3. Under dynamic conditions, null-type instruments are less preferred to deflection-type instruments. 4. Response is faster in null-type instruments as compared to deflection-type instruments. Which of the above statements are correct?
A certain inverting amplifier has a closed-loop voltage gain of 25. The OP-amp has an open-loop voltage gain of 100,000. If an OP-amp with an open-loop voltage gain of 200,000 is substituted in the arrangement, the closed-loop gain
The mixing vat in a factory receives liquid ingredients through six separate value--- labeled R.S.T.U,Y and Z -- each of which has exactly two settings: open and closed.The mixing vat operator must ensure that each valve is set open or closed according to the following conditions: If T is open, both S and Z must be closed, R and Z cannot both be closed at the same time; If Y is closed, Z must also be closed;S and U cannot both be open at the same time. If Z is open, which of the following must be true?
The mixing vat in a factory receives liquid ingredients through six separate value--- labeled R.S.T.U,Y and Z -- each of which has exactly two settings: open and closed.The mixing vat operator must ensure that each valve is set open or closed according to the following conditions: If T is open, both S and Z must be closed, R and Z cannot both be closed at the same time; If Y is closed, Z must also be closed;S and U cannot both be open at the same time. Which of the following, if given to the mixing vat operator as an instruction, would not determine the setting of any other valve ?
Consider the following statements for deflection and null type instruments: 1. Deflection type of instruments are more accurate than null type of instruments. 2. Deflection type of instruments can be highly sensitive as compared with the null type of instruments. 3. Null type of instruments are more suitable for measurements under dynamic conditions than deflection type of instruments. Which of the above statements are not correct?
The height of a tree is defined as the number of edges on the longest path in the tree. The function shown in the pseudocode below is invoked as height(root) to compute the height of a binary tree rooted at the tree pointer root. int height (treeptr n) { if (n == NULL) return -1;   if (n →  left == NULL)        if (n →  right == NULL) return 0;        else return ; \(\boxed{B1}\);     // Box 1 else { h1 = height (n →  left);          if (n → right == NULL) return (1+h1);          else { h2 = height (n → right);          return ; \(\boxed{B2}\)   // Box 2                        }            } } The appropriate expressions for the two boxes B1 and B2 are
Point out the error (if any) in the following C code?
#include #include int main(void){ int* p = NULL; struct S *s = NULL; void(*f)(int, double) = NULL; char *ptr = malloc(15); if (ptr == NULL) printf("Out of memory"); free(ptr);}